Answer:
[tex]4y+3\leq y+6[/tex]
We solve for [tex]y[/tex]
[tex]4y-y\leq 6-3\\3y\leq 3\\y\leq 1[/tex]
The solution set is all number less or equal than 1. Its graph is C, because it shows the right solution set.
[tex]-2y>2\\y<\frac{2}{-2}\\ y<-1[/tex]
The solution set is all numbers less than -1. Its graph is A, because it represents all number less than -1. (The empty circle means that -1 is not part of the solution set, which is true)
[tex]\frac{y}{3}<-1\\ y<-3[/tex]
The solution set is all numbers less than -3. Its graph is D.
[tex]3y\leq 2y+3\\3y-2y \leq 3\\y \leq 3[/tex]
The solution set is all numbers less or equal than 3. Its graph is B, because it shows exactly the solution set.
