Respuesta :
[tex]\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &20700\\
r=rate\to 13.75\%\to \frac{13.75}{100}\to &0.1375\\
t=\textit{elapsed time}\to &12\\
\end{cases}
\\\\\\
A=20700(1-0.1375)^{12}\implies A=20700(0.8625)^{12}[/tex]
