Respuesta :

shawnkat
Hey there!

In order to write the slope-intercept form, we have to have slope, and the y intercepts, just as it says in the name. In order to find slope with two points, we use our formula:

y2-y1/x2-x1 =
6-(-4)/0-2 = 6+4/-2 =
10/-2 = -5

Now that we know our slope is negative five, we can use one of those poins to model our slope intercept form, y= mx+b, using our slope, to solve for b, our y intercepts. We'll use (0,6).

We have:

6 = -2(0) + b
6 = 0 + b
6 = b

Now, since we have the slope and y intercept, we can write the equation:

y = -2x + 6

Hope this helps!
calculista

we know that

the equation of the line in the slope-intercept form is equal to

[tex]y=mx+b[/tex]

where

m is the slope of the line

b is the y-intercept of the line

Let

[tex]A(2,-4)\\B(0,6)[/tex]

Step [tex]1[/tex]

Find the slope of the line AB

the slope between two pints is equal to

[tex]m=\frac{(y2-y1)}{(x2-x1)}[/tex]

substitute the values

[tex]mAB=\frac{(6+4)}{(0-2)}[/tex]

[tex]mAB=\frac{(10)}{(-2)}[/tex]

[tex]mAB=-5[/tex]

with the slope m and the point B find the value of b

[tex]B(0,6)[/tex]

[tex]6=-5*0+b[/tex]

[tex]b=6[/tex]

Find the equation of the line

[tex]y=mx+b[/tex]

[tex]y=-5x+6[/tex]

therefore

the answer is

[tex]y=-5x+6[/tex]


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