Solve the following word problem. A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y?

______ miles

Respuesta :

10 miles per hour from Town X to Town Y

Distance from Town X to Town Y = 100 miles

Distance = Speed x Time

Speed while going = 50 mph , Speed while returning = 40 mph

Let the time taken while going = t hours

So, the time taken while returning = t + 0.5 hours

  • Distance while going = Distance while coming back

So, 50 t = 40 ( t + 0.5)

50 t = 40x + 20

50 t - 40 t = 10x = 20

10 t = 20

t = 20 / 10 = 2

Hence, distance = 50 t = 40 ( t + 0.5 )

= 50 x 2 ; or 40 x 2.5 = 100  

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