Respuesta :
Since, a bicyclist was traveling from the village to the railroad station with a speed of 15 mph and he was coming back to the village with a speed of 10 mph.
Let the time taken in traveling from village to the railroad station be 't' hours
Distance is calculated by the formula:
[tex] d= s \times t [/tex]
So, the distance traveled from village to the railroad station is:
[tex] d=15 \times t [/tex]
Since, the time taken in traveling from railroad station to the village is 1 hour more = 't+1' hours
So, the distance traveled from railroad station to the village is:
[tex] d=10 \times (t+1) [/tex]
Therefore, distance traveled from village to railroad station is equals to the distance traveled from railroad station to the village.
So, [tex] 15 \times t=10(t+1) [/tex]
[tex] 15t=10t+10 [/tex]
[tex] 5t=10 [/tex]
So, t=2
Therefore, distance from village to railroad station = [tex] 15 \times t [/tex]
= [tex] 15 \times 2 [/tex]
= 30 miles.
Therefore, the distance from village to railroad station is 30 miles.
The distance from the village to the railroad station is 30 miles
Speed is the ratio of distance to time taken. It is given by:
Speed = distance/time
Let d represent the distance from the village to the rail station.
When Going at a speed of 15mph, let us assume he spent a hour, hence:
15 = d/a
d = 15a
When coming at a speed of 10mph, let us assume he spent b hour, hence:
10 = d/b
d = 10b
Therefore:
15a = 10b
But it took 1 more hour for the bicyclist to get back to the village, hence b = a + 1, hence:
15a = 10(a + 1)
15a = 10a + 10
5a = 10
a = 2 hours
d = 15a = 15(2) = 30 miles
Therefore, the distance from the village to the railroad station is 30 miles
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