Respuesta :
Solution.
Initial angular velocity ωi = 0.330 × 2π rad/sec
= 2.0737 rad/sec
The initial moment of inertia li = 0.5×M×r²
= 0.5 × 120 × 1.8²
= 194.4 kgm²
But the angular momentum is given by the product of moment of inertia and the angular velocity.
= li × ωi
= 2.0737 × 194.4
= 403.13 kg.m²/s which is constant
Child moment of inertia (point mass) = m × r²
= 27.5 × 1.8²
= 27.5 × 3.24
= 89.1 kgm²
Thus, the final moment of inertia if = 194.4 + 89.1 = 283.5 kgm²
Therefore; the final speed: =403.13/ 283.5
= 1.422 rad/sec
This is equivalent to;
1.422/2π = 0.2263 rev/s
Initial angular velocity ωi = 0.330 × 2π rad/sec
= 2.0737 rad/sec
The initial moment of inertia li = 0.5×M×r²
= 0.5 × 120 × 1.8²
= 194.4 kgm²
But the angular momentum is given by the product of moment of inertia and the angular velocity.
= li × ωi
= 2.0737 × 194.4
= 403.13 kg.m²/s which is constant
Child moment of inertia (point mass) = m × r²
= 27.5 × 1.8²
= 27.5 × 3.24
= 89.1 kgm²
Thus, the final moment of inertia if = 194.4 + 89.1 = 283.5 kgm²
Therefore; the final speed: =403.13/ 283.5
= 1.422 rad/sec
This is equivalent to;
1.422/2π = 0.2263 rev/s
