Answer:
[tex]\text {Area of figure is }44 units^2[/tex]
Step-by-step explanation:
Given the figure and we have to find the area of given figure.
Area of figure=ar(ABC)+ar(CDE)+ar(AEFH)+ar(GHF)
From the figure, dimensions according to square boxes can be written as
AE=HF=8 units, EF=3 units, BI=3 units, GH=2 units, AC=CE=4 units.
[tex]ar(ABC)=ar(CDE)=\frac{1}{2}\timesAC\times BI=\frac{1}{2}\times4\times3=6 units^2[/tex]
[tex]ar(AEFH)=HF\times EF=8\times 3=24 units^2[/tex]
[tex]ar(GHF)=\frac{1}{2}\timesHF\timesGH=\frac{1}{2}\times8\times 2=8units^2[/tex]
∴ [tex]\text {Area of figure is }44 units^2[/tex]
