Respuesta :

[tex] 4|x + \dfrac{1}{3}| = 20 [/tex]

[tex] |x + \dfrac{1}{3}| = 5 [/tex]

[tex] x + \dfrac{1}{3} = 5 [/tex]   or   [tex] x + \dfrac{1}{3} = -5 [/tex]

[tex] x = 5 - \dfrac{1}{3} [/tex]   or   [tex] x = -5 - \dfrac{1}{3} [/tex]

[tex] x = 4 \dfrac{2}{3} [/tex]   or   [tex] x = -5 \dfrac{1}{3} [/tex]
Selection C is appropriate.

Divide by 4, unfold, subtract 1/3.
.. |x +1/3| = 5
.. -5 = x +1/3 . . . . one choice for the sign of the content of |x +1/3|
.. -5 1/3 = x

.. x +1/3 = 5 . . . . the other choice
.. x = 4 2/3

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If this were an inequality |x +1/3| < 5, I would "unfold" it as
.. -5 < x +1/3 < 5 . . . . . . . copy the right side expression to the left with reversed sign.
The above is an approximation of that. You can't really write -5 = ( ) = 5, because it is a gross violation of the equal sign. But you can write the two versions:
.. -5 = ( )
.. ( ) = 5
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