The point slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y-1- 1-12). What is the standard form of the equation for this line?
The point-slope form of the equation through those points is .. y -1 = (1/4)(x -12) Multiply by 4 and subtract the left side to put into general form. .. x -12 -4(y -1) = 0 .. x -4y -8 = 0 Add 8 to put into standard form .. x -4y = 8
