tickets to a science exposition cost $5.75 each for students and $7.00 for adults. How many students and adults went if the ticket charge was $42.75?

Well this is a pretty fun problem that involves variables.
let's set some variables
s = students
a = adults
the total is
42.75
so let's solve for one variable
42.75 = 7.00a + 5.75s

let's just plug in a number for a I'm going to go with two and let's solve for s
42.75 = 7.00(2) +5.75s
42.75 =14.00 + 5.75s
28.75 = 5.75s
28.75/5.75 = s
5=s
so
so the amount of students and adults that can go is 2 adults and 5 students

Answer Link

vidalmari6p99qfk vidalmari6p99qfk · Answer 2 · 2019-08-03T21:50:03+02:00

Answer: 2 Adults 5 children

Step-by-step explanation

5.75(s) + 7.00

1 ticket = $5.75

2 tickets = $11.50

3 tickets = $17.25

4 tickets = $23.00

5 tickets = $28.75

Only tickets that add with an ending .75 can be substracted from 42.75 in order to get an even number since adult tickets are even number

1 ticket: $42.75 - $5.75 = $37.00

5 tickets: $42.75 - $28.75 = $14.00

9 tickets: $42.75 - $51.75 = -$9.00

It is either 1 student or 5 students

If you divide $14 into 7 (price for adult ticket) the result is 2