(1, −3)(i) find polar coordinates (r, θ) of the point, where r > 0 and 0 ≤ θ < 2π.(r, θ) = incorrect: your answer is incorrect. (ii) find polar coordinates (r, θ) of the point, where r < 0 and 0 ≤ θ < 2π.(r, θ) =
the relationship between the 2-dimensional polar and Cartesian coordinates is
r = √(x² + y²) Θ = tan⁻¹ (y/x) so point (1, -3)---------> this point belong to the IV quadrant r = √(x² + y²)------ r = √(1² + (-3)²)-----> r=√10 Θ = tan⁻¹ (y/x)---- Θ = tan⁻¹ (3/1)----> 71.57° remember that the point belong to the IV quadrant so Θ=360-71.57-----> Θ=288.43°
