The length of a rectangle is 5/2 units greater than twice its width. If its width is w, which expression gives the perimeter of the rectangle in terms of w? A. 2(5/2 w) + w B. 5/2 w + w C. 3 w + 10/2 D. 6 w + 5

Width = w
Length = 2w + 5/2

Perimeter = 2(Length + Width)
Perimeter = 2( w + 2w + 5/2)
Perimeter = 2(3w + 5/2)
Perimeter = 6w + 5

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Answer: The perimeter is 6w + 5 (Answer D)
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david8644 david8644 · Answer 2 · 2019-10-03T19:41:48+02:00

Answer:

D. 6 w + 5

Step-by-step explanation:

In order to solve this you first have to express the length and width of the rectangle in terms of W:

Width= W

Length= 5/2 units more than twice its width= 2w + 5/2

No we just have to add that up in an equation, using the formula for perimeter:

[tex]Perimeter= 2(width) + 2(length)\\Perimeter=2w+ 2(2w + \frac{5}{2})\\Perimeter= 2w+4w+5\\Perimeter= 6w +5[/tex]

SO we know that the perimeter expressed in terms of w is equal to 6w +5 units.