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Consider the two functions given below.
f(x) = 3x + 4
g(x) = 2^x - 1

Which of the following pairs of transformations causes the graphs of the functions to have the same y-intercept?

f(x) - 3 and g(x) + 1

f(x) + 4 and g(x) - 1

f(x) - 2 and g(x) + 1

f(x) + 3 and g(x) - 6

Respuesta :

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This means which transformation makes the same answer at x = 0

f(x) = 3x + 4
[tex] g(x) = {2}^{x} - 1[/tex]

f(0) = 4
g(0) = 1 - 1 = 0

Which transformation makes 4 = 0?

4 + x = 0 + y

4 - 3 =0 + 1

1 = 1

Option 1 is your answer
Blacklash

Answer:

Option A is the correct answer.

Step-by-step explanation:

y intercept means x value is 0.

f(0) = 3 x 0 + 4 = 4

[tex]g(0)=2^0-1=1-1=0[/tex]

We need same y intercepts

 That is f(0) = g(0)

           4 + a = 0 + b

Checking all the options

a) f(x) - 3 and g(x) + 1

          4 - 3 and 0 + 1

              1 and 1

    Option A is correct.

b) f(x) + 4 and g(x) - 1

          4 + 4 and 0 - 1

              8 and -1

    Option B is wrong.

c) f(x) - 2 and g(x) + 1

          4 - 2 and 0 + 1

              2 and 1

    Option C is wrong.

d) f(x) + 3 and g(x) - 6

          4 + 3 and 0 - 6

              7 and -6

    Option D is wrong.

So, Option A is the correct answer.

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