A 6.0 mol sample of C3H8(g) and a 20. mol sample of Cl2(g) are placed in a previously evacuated vessel, where they react according to the equation above. After one of the reactants has been totally consumed, how many moles of HCl(g) have been produced?
2 CH₃CH₂CH₃ + 2 Cl₂ → CH₃CH(Cl)CH₃ + CH₃CH₂CH₂Cl + 2 HCl so according to balanced equation we notice that: 2 mole of propane reacts with 2 moles of Cl₂, so 6 moles of propane will need to react completely with 6 moles Cl₂ (This mean Cl₂ present in excess and propane is the Limiting reagent) 2 mole C₃H₈ gives 2 moles HCl 6 moles C₃H₈ gives ? moles HCl by cross multiplication we have 6 moles of HCl formed
