The magnetic force is given as: F = qvBsinФ
where Ф is the angle between magnetic field (B) & the velocity of charge (v).
Since there is no Ф given, we assume, Ф = 90.
And we know, sin 90 = 1, we get,
⇒ F = qvB
⇒ F = 1.6×10^(-19) C ×2.5×10^(7)×0.12 T
⇒ F = 0.48 × 10^(-12)
or F = 4.8 × 10^(-13)
Now, using flemingo's left hand rule to find the direction (right).
Attached is the image.
