To do this problem, you need to figure out how reliable the bus is by converting the fraction the bus is on-time to a percentage. That way you can compare the percentage of time the train is on-time to the percentage of time the bus is on time.
To do this, you would need to divide the amount of days the bus was on-time, 56, by the total amount days, 64, and multiply the decimal you get by 100% to get the percentage. then compare that percentage to the percentage that the train was on-time.
I will do the rest of problem below, just in case, but you can try it out on your own :)
So the bus is on-time:
[tex] \frac{56}{64} \times 100\% = 87.5\%[/tex]
of the time.
The train was on time 90% of the time and the bus was on time 87.5% of the time. That means the train was more reliable.
