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Evan bought two square rows the larger one measure 12 ft Square the smaller one had an area equal to 1/4 the area of the larger one what fraction of the side length of the larger rug with a side length of the smaller one

Respuesta :

carlosego
The smallest area is:
 A2 = (1/4) * (A1)
 Substituting:
 A2 = (1/4) * (12)
 A2 = 3 feet ^ 2
 Since both are squares then:
 L2 = root (3)
 L1 = root (12)
 The relationship is:
 L2 / L1 = (root (3)) / (root (12))
 Rewriting:
 L2 / L1 = (root (3)) / (root (3 * 4))
 L2 / L1 = (root (3)) / (2raiz (3))
 L2 / L1 = 1/2
 Answer:
 The fraction of the side length of the larger rug with a side length of the smaller one is:
 L2 / L1 = 1/2

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