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Mole ratios represent quantities of substances in the chemical equation by proportion. Each answer can be stated in vice versa.

Answers for A are the following:
2 moles of HgO form 2 moles of Hg
2 moles of HgO form 1 moles of O2
2 moles of Hg to 1 mole of O2

Answers for B are the following:
4 moles NH3 to 6 moles NO
5 moles N2 to 6 moles H2O
4 moles NH3 to 5 moles N2
4 moles NH3 to 6 moles H2O
6 moles NO to 5 moles N2
6 moles NO to 6 moles H2O

Mole ratio is defined as the ratio or relation of two elements or compounds in a chemical reaction. It is the ratio of coefficients of the balanced chemical equation.

A. The given equation is:

2 HgO(s) [tex]\rightarrow[/tex] 2 Hg (l) + O₂ (g)

From the balanced chemical equation, the possible mole ratios are:

[tex]\dfrac{\text {2 moles of HgO}}{\text{2 moles of Hg}}\\\\\dfrac{\text {2 moles of HgO}}{\text{1 moles of O}_2}\\\\\dfrac{\text {2 moles of Hg}}{\text{1 moles of O}_2}[/tex]

B. Similarly, for the other equation:

4 NH₃ (g) + 6 NO (g) [tex]\rightarrow[/tex] 5 N₂ (g) + 6 H₂O (l)

The possible mole ratios are:

[tex]\dfrac{\text {4 moles of NH}_3}{\text{6 moles of NO}}\\\\\dfrac{\text {4 moles of NH}_3}{\text{5 moles of N}_2}\\\\\dfrac{\text {4 moles of NH}_3}{\text{6 moles of H}_2 \text O}}\\\\\dfrac{\text {6 moles of NO}}{\text{5 moles of N}_2}\\\\\dfrac{\text {6 moles of NO}}{\text{6 moles H}_2 \text O}}\\\\\dfrac{\text {5 moles of N}_2}{\text{6 moles H}_2 \text O}}[/tex]

Thus, before calculating the enthalpy change or solving the equation, the equation should be balanced.

The law of conservation of mass is followed and the conclusion obtained is correct. The mole ratios can be incorrect if the equation is not balanced and stoichiometrically not correct.

To know more about mole ratio, refer to the following link:

https://brainly.com/question/9413308

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