A truck is carrying 8 cars weighing an average of 4,500 pounds each.What is the total weight in tons the cars on the truck?

Ben's living room is a rectangle measuring 10 yards by 168 inches. By how many feet does the length of the room exceed the width?

Respuesta :

klee48
4500(8)=36000 pounds in total
Each car weighs 4500 pounds. There are 8 cars in total.

168/12=14 feet

3 feet in 1 yard
30 feet

30-14=16 feet

Answer: The total weight in tons the cars on the truck= 18 tons.

The length of the room exceed the width by 16 feet.


Step-by-step explanation:

a) Given: Weight of 1 truck=4500 pounds

Thus, weight of 8 trucks= [tex]8\times4500[/tex] pounds

[tex]=36000\ pounds[/tex]

We know that 1 ton=2000 pounds

Thus, weight of 8 trucks in tons=[tex]\frac{36000}{2000}=18\ tons[/tex]

Hence, the total weight in tons the cars on the truck= 18 tons.

b) Given: Dimensions of the room are as

Length=10 yards and width= 168 inches

We know that 1 yard=3 feet and 1 inch=[tex]\frac{1}{12}\ foot[/tex]

Thus, length[tex]=10\times3=30\ feet[/tex]

width=[tex]168\times\frac{1}{12}=14\ feet[/tex]

The difference between length and width=[tex]length-width=30-14=16\ feet[/tex]

Hence, the length of the room exceed the width by 16 feet.