Answer:
36 degrees
Step-by-step explanation:
Refer the attached figure .
Height of tree i.e. AB = 10 yards
Length of shadow i.e. BC = 14 yards .
We are required to find the angle of elevation from the tip of the shadow to the top of the tree. i.e. ∠ACB
Now, we will use trigonometric ratio.
[tex]tan\theta = \frac{Perpendicular}{Base}[/tex]
[tex]tan\theta = \frac{AB}{BC}[/tex]
[tex]tan\theta = \frac{10}{14}[/tex]
[tex]tan\theta =0.714[/tex]
[tex]\theta =tani^{-1}0.714[/tex]
[tex]\theta =35.52^{\circ}[/tex]
Thus the angle of elevation is 35.52° ≈ 36°
Hence the angle of elevation from the tip of the shadow o the top of the tree. i.e. ∠ACB is 36°
