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If the frequency of oscillation of the wave emitted by an fm radio station is 92.4 mhz, determine the wave's period of vibration

Respuesta :

skyluke89
The basic relationship between the frequency of a wave and its period is
[tex]f= \frac{1}{T} [/tex]
where f is the frequency and T the period of vibration.

In our problem, the frequency is 
[tex]f=92.4 MHz = 92.4 \cdot 10^6 Hz[/tex]
so, by re-arranging the previous formula, we can find the period of the wave:
[tex]T= \frac{1}{f}= \frac{1}{92.4 \cdot 10^6 Hz}=1.1 \cdot 10^{-8} s [/tex]
shubhamchouhanvrVT

The period of the wave with the frequency of 92.4 Mega hertz will be [tex]T=1.1\times 10^{-8}\ S[/tex]

What is a period of the wave?

The period of the wave is defined as the time taken by the wave to complete one cycle .The period of the wave is inverse of the frequency of the wave.

[tex]T=\dfrac{1}{f}[/tex]

Now it is given in the question that

Frequency of the wave f=92.4 mega herts

[tex]f= 92.4\times 10^6\ hertz[/tex]

Now the time period will be:

[tex]T=\dfrac{1}{92.4\times 10^6}[/tex]

[tex]T=}1.1\times 10^{-8}\ S[/tex]

Hence the period of the wave with the frequency of 92.4 Mega hertz will be [tex]T=1.1\times 10^{-8}\ S[/tex]

To know more about the period of the wave follow

https://brainly.com/question/1270198

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