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A balloon is filled with helium at sea level. The volume was measured to be 3.1 liters at a pressure of 0.97 atmosphere. If the balloon is released, it drifts upward. At a height of 4 kilometers, the pressure is measured to be 0.61 atmospheres. What is the volume of the balloon?


Respuesta :

P1V1=P2V2 Boyle's law
0.97atm × 3.1L= 0.61atm × V2
V2= 4.9L

Answer:

The volume of the balloon is 4.92 L at the height of 4 km.

Explanation:

Initial Volume of the helium gas [tex]V_1= 3.1 L[/tex]

Initial pressure of the helium gas [tex]P_1= 0.97 atm[/tex]

Final volume of the helium gas = [tex]V_2[/tex]

Final pressure of the helium gas =[tex]P_2=0.61 atm[/tex]

Applying Boyle's law:

[tex]P_1V_1=P_2V_2[/tex] (At constant temperature)

[tex]V_2=\frac{P_1\times V_1}{P_2}=\frac{0.97 atm\times 3.1 L}{0.61 L}[/tex]

[tex]V_2=4.92 L[/tex]

The volume of the balloon is 4.92 L at the height of 4 km.

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