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By what factor will the rate of the reaction change if the ph decreases from 6.00 to 2.00? express your answer numerically using two significant figures. view available hint(s)

Respuesta :

superman1987
The reaction equation is first order with respect to [H+]

when PH1 = -㏒[H+]1  so, when PH = 6

So by substitution:

∴ 6 = -㏒[H+]1

∴[H+]1 = 1 x 10^-6

and when PH2 = -㏒[H+]2 so, when PH2 = 2

so by substitution:

∴ 2 = -㏒[H]2

∴[H]2 = 1 x 10^-2

So the rate of reaction changes by the factor of:

[H2]2/[H]1 = (1 x 10^-2) / (1 x 10^-6) = 10000

It is 10000 times faster when PH decreases from 6 to 2

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