Respuesta :
Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
[tex] {x}^{2} + {x}^{2} = {10}^{2} [/tex]
[tex]2 {x}^{2} = 100[/tex]
[tex] {x }^{2} = 50[/tex]
[tex]x = \sqrt{50} [/tex]
side of a diagonal=2 sqrt50
[tex] = 10 \sqrt{2} [/tex]
cm......
HOPE IT HELPS YOU '_'
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
[tex] {x}^{2} + {x}^{2} = {10}^{2} [/tex]
[tex]2 {x}^{2} = 100[/tex]
[tex] {x }^{2} = 50[/tex]
[tex]x = \sqrt{50} [/tex]
side of a diagonal=2 sqrt50
[tex] = 10 \sqrt{2} [/tex]
cm......
HOPE IT HELPS YOU '_'
a² + b² = c²
c² = 10² + 10²
c² = 100 + 100
c² = 200
c = √200
c = 10√2
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Answer : The length of the diagonal is 10√2.
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c² = 10² + 10²
c² = 100 + 100
c² = 200
c = √200
c = 10√2
--------------------------------------------------------------------
Answer : The length of the diagonal is 10√2.
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