The rider has a mass of 100 kg. When travelling downward from point E to D, he reaches a velocity of 11 m/s. Calculate his kinetic energy at D (show your work). (KE= ½ mv2)
I am going to assume that the rider starts at rest. Using the equation for kinetic energy, the answer would be equivalent to [tex] \frac{1}{2} (100)(11)^2[/tex]. The final answer would be 50 N.
