Question
what are the first four terms of the sequence given by the formula below? [tex]a_{n}[/tex]=-2n+4
A) -6, -8, -10, -12
B) -2, 0, 2, 4
C) 2, 0, -2, -4
D) 6, 8, 10, 12
Answer & Step-by-step explanation:
[tex]a_{n}[/tex]=-2n+4 ; where n is the sequence number or order.
[tex]a_{1}[/tex] = -2(1) + 4
[tex]a_{1}[/tex] = -2 + 4
[tex]a_{1}[/tex] = 2
[tex]a_{2}[/tex] = -2(2) + 4
[tex]a_{2}[/tex] = -4 + 4
[tex]a_{2}[/tex] = 0
[tex]a_{3}[/tex] = -2(3) + 4
[tex]a_{3}[/tex] = -6 + 4
[tex]a_{3}[/tex] = -2
[tex]a_{4}[/tex] = -2(4) + 4
[tex]a_{4}[/tex] = -8 + 4
[tex]a_{4}[/tex] = -4
So the first four terms of the sequence are: C) 2, 0, -2, -4
