To solve this problem you must follow the proccedure below:
a. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of the cracker remaining is:
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=πr²/4
A=π(3 cm)²/4
A=7.06 cm²
The area ofof the cracker remaining is:
At=Area of a square-Area of quarter circle
At=L²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
b. About how many bites can you get from the entire cracker?
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
