There is no figure, so I asume the angle of the rope is measured with respect to the horizontal direction.
If this is the case, then the magnitude of the tension is the hypothenuse of a right triangle, of which [tex]T_x [/tex] and [tex]T_y [/tex] (horizontal and vertical component of the tension) are the other sides, and [tex]\alpha[/tex] is the angle between T and [tex]T_x[/tex].
Therefore, [tex]T_y[/tex] (the side of the triangle opposite to [tex]\alpha[/tex]) is given by the magnitude of the tension multiplied by the sine of the angle:
[tex]T_y = T \sin \alpha = (650 N)(\sin 27^{\circ} )=295 N[/tex]
