When heat (q) is absorbed by "m" grams of a substance then the change in temperature is given as,
q = m Cp (T₂ - T₁) --- (1)
where;
Cp = Specific Heat
Specific heat of Benzene is 1.72 J/g.°C
Now,
Solving equation 1,
(T₂ - T₁) = q / m Cp
Putting values,
(T₂ - 30 °C) = 2500 J ÷ (120 g ×1.72 J/g.°C)
(T₂ - 30 °C) = 2500 J ÷ (206 J/°C)
(T₂ - 30 °C) = 12.13 °C
T₂ = 12.13 °C + 30 °C
T₂ = 42.13 °C
