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∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 28°, minor arc AB = 112°, and minor arc DE = 112°, what is the measure of ∠ACE? A) 14° B) 28° C) 40° D) 54°

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D) 54 degrees:

BD+AB+DE+2ACE" on the circumference twice on the center"=360

28+112+112+2ACE=360

2ACE=108

∠ACE=54

Answer:

its 40 degrees

Step-by-step explanation:

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