Mike ate 1 / 3 of a bag of peanuts at the game, then there left
[tex] 1-\dfrac{1}{3} =\dfrac{3}{3} -\dfrac{1}{3}=\dfrac{2}{3} [/tex].
On the way home he ate 1 / 3 of what was left, that is he ate 1 / 3 from 2 / 3 and this is
[tex] \dfrac{1}{3} \cdot \dfrac{2}{3} =\dfrac{1\cdot 2}{3\cdot 3} =\dfrac{2}{9} [/tex].
On the way home Mike ate 2 / 9 of a bag of peanuts.
Answer: Correct choice is D.
