Respuesta :

gmany
[tex]-6x-\dfrac{17}{4}\leq\dfrac{79}{4}\ \ \ |\cdot4\\\\-24x-17\leq79\ \ \ |+17\\\\-24x\leq96\ \ \ |:(-24)\\\\x\geq-4\to x\in\left<-4;\ \infty\right)[/tex]