Respuesta :
Given:
B = [tex] 3 \times 10^{2} [/tex] T
V=[tex] 5 \times 10^{3} \frac{m}{s} [/tex]
q = 2.5 × [tex] 10^{-6} [/tex] C
α = 90
To find:
Force = ?
Formula used:
Force on the moving charge is given by,
F = q V B sin α
Where F = force exerted on moving charge
V = velocity of charge
q = charge
α = angle between direction of V and B
Solution:
F = q V B sin α
Where F = force exerted on moving charge
V = velocity of charge
q = charge
α = angle between direction of V and B
F = [tex] 2.5 \times 10^{-6} \times 3 \times 10^{2} \times 5 \times 10^{3} [/tex]
F = 37.5 × [tex] 10^{-1} [/tex]
F = 3.75 Newton
Thus, the force acting on the moving charge is 3.75 Newton.
