Solve triangle PQR is PQ 9, PR 7, and QR 8. POR is NOT a right triangle.

Given => PQ = 9 unit
PR = 7 unit
QR = 8 unit

To find => Area of triangle PQR

We can find area of triangle by Heron's Formula.

Where,

s = (9+7+8)/3

= 24/3

= 8

and,
a = 9
b = 7
c = 8

Heron's Formula = [tex] \sqrt{s(s - a)(s - b)(s - c)} [/tex]

= [tex] \sqrt{8(8 - 9)(8 - 7)(8 - 8)} [/tex]

= [tex] \sqrt{8( - 1)(1)} [/tex]

= [tex] \sqrt{ - 8} [/tex]

= [tex]2i \sqrt{2} [/tex]

Area of triangle = 2i√2 units

Hope this helps!

Answer Link

Аноним Аноним · Answer 2 · 2018-05-02T06:18:13+02:00

We will solve this using Heron's Formula for the area of a triangle.

[tex]\text {Formula = } \sqrt{p(p-a)(p-b)(p-c)} , \text { where p is half the perimeter}[/tex]

We will start off by find p:

[tex]\text {p = } \dfrac{9+7+8}{2} = \dfrac{24}{2}= 12 [/tex]

Now we know, p = 12, we plug in a = 9, b = 8 and c = 7 into the formula to find the area:

[tex]\text {area = } \sqrt{12(12-9)(12-8)(12-7)}[/tex]

[tex]\text {area = } \sqrt{12(3)(4)(5)}[/tex]

[tex]\text {area = } 26.83 \text{ units}^2[/tex]