Respuesta :
where are the choices?
the answer could be that both parents are carrying the heterozygous genes. so let's say B is the dominant brown eye gene and b is the recessive blue eye gene. both parents could possess the Bb genotype, and hence by using test cross, Tim was that 25% chance where a child could inherit the bb genotype to have blue eyes
the answer could be that both parents are carrying the heterozygous genes. so let's say B is the dominant brown eye gene and b is the recessive blue eye gene. both parents could possess the Bb genotype, and hence by using test cross, Tim was that 25% chance where a child could inherit the bb genotype to have blue eyes
If Tim has blue eyes, then both of his parents are heterozygous for the brown eye trait.
Here would be the alleles:
BB-Homozygous Dominant for brown eyes
Bb-Heterozygous for brown eyes
bb-Homozygous Recessive for blue eyes
If you input the heterozygous allele for brown eyes into a punnet square, you would get a 25% chance of homozygous brown eyes, 50% chance of heterozygous brown eyes and a 25% chance of homozygous recessive blue eyes. Tim is that 25% that received a trait for blue eyes.
Here would be the alleles:
BB-Homozygous Dominant for brown eyes
Bb-Heterozygous for brown eyes
bb-Homozygous Recessive for blue eyes
If you input the heterozygous allele for brown eyes into a punnet square, you would get a 25% chance of homozygous brown eyes, 50% chance of heterozygous brown eyes and a 25% chance of homozygous recessive blue eyes. Tim is that 25% that received a trait for blue eyes.
