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In fruit flies, the allele for vestigial wings is recessive to the allele for wild-type wings, and the allele for white eyes is recessive to the allele for red eyes. the gene controlling wing type is carried on an autosome, whereas the gene controlling eye color is carried on the x chromosome. a true-breeding female with wild-type wings and white eyes is crossed with a male with vestigial wings and red eyes. what proportion of the offspring are expected to be males with wild-type wings and white eyes? give your answer as a fraction or a decimal value from 0 to 1.

Respuesta :

Low wings with red eyes -LR
Vestigial wings brown eyes - Lr
Red-eyed, the vestigial winged male is crossed with brown-eyed, long-winged female. Each parent is homozygous for the dominant alleles
llRR    LLrr
gametes LR   lr
F1 LlRr with only one genotype and ratio is 1
Long-winged red eyes phenotype its ratio is also 1
Each parent is heterozygote for the dominant alleles
llRr   llrr
gametes  lR lr Lr lrF1 LlRr  llRr  Llrr  llrr
then the genotype ratio is 1: 1: 1: 1












































lr  lr



Andouhaoyu0704

Answer:

Both parents were heterozygous

Explanation:

Lets suppose N is the dominant and n is the recessive.

If both parents are heterozygous, they can create flies with vestigial and normal wings. The result of that is 25% NN, 50% Nn, and 25% nn. If you add up the flies that were vestigial and the flies that were normal, it would be 120. The male and female flies with vestigial wings add up to be 33, 33/120 is 27.5% which is a little over 25%.

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