Answer:
6√3
Explanation:
Before we begin, remember the following:
[tex] \sqrt{a*b} = \sqrt{a} * \sqrt{b} [/tex]
[tex]m \sqrt{a} + n \sqrt{a} = (m+n) \sqrt{a} [/tex]
Now, for the given:
75 can be written as 25*3
This means that:
[tex] \sqrt{75} = \sqrt{25*3} [/tex]
Applying the above concept, we can find that:
[tex] \sqrt{75} = \sqrt{25*3} = \sqrt{25} * \sqrt{3} [/tex]
Now, we know that:
√25 = 5 (we ignored the negative value)
This means that:
√75 = 5√3
Finally, we can compute the needed sum as follows:
√75 + √3 = 5√3 + √3 = 6√3
Hope this helps :)
