A spinner is to be used during a probability experiment. The spinner is separated into all congruent sections of which 8 sections are orange, 4 sections are yellow, and 2 sections are green. What is the probability written in simplest form that the spinner will NOT stop on a green section during the first spin?

Respuesta :

Not green...means orange or yellow

Total sections=8+4+2=14, orange and yellow sections=8+4=12

P(y or o)=12/14

P=6/7  (about 85.7%)

[tex] |\Omega|=14\\
|A|=12\\\\
P(A)=\dfrac{12}{14}=\dfrac{6}{7}\approx86\% [/tex]