Answer:
[tex] \frac{25-y^2}{16} + \frac{y^2}{9} = 1[/tex]
Explanation:
For the first given equation, we will need to isolate the x². This can be done as follows:
x² + y² = 25
x² + y² - y² = 25 - y²
x² = 25 - y² ..................> I
For the second given equation:
We will remove every x² and substitute with its equivalence from I as follows:
[tex] \frac{x^2}{16} + \frac{y^2}{9} = 1[/tex]
[tex] \frac{25-y^2}{16} + \frac{y^2}{9} = 1[/tex]
Hope this helps :)
