Uppose a jar contains 12 red marbles and 18 blue marbles. if you reach in the jar and pull out 2 marbles at random without replacement, (a) find the probability of getting two red marbles:

Respuesta :


[tex] \frac{12}{30} \times \frac{11}{29} = \frac{22}{145} [/tex]

[tex] \displaystyle
|\Omega|=\binom{30}{2}=\dfrac{30!}{2!28!}=\dfrac{29\cdot30}{2}=435\\
|A|=\binom{12}{2}=\dfrac{12!}{2!10!}=\dfrac{11\cdot12}{2}=66\\\\
P(A)=\dfrac{66}{435}=\dfrac{22}{145}\approx15\% [/tex]