The balance chemical equation is as follow,
Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag
First calculate for 200 g of AgNO₃,
According to equation,
339.74 g (2 mole) AgNO₃ produced = 215.7 g (2 mole) of Ag
So,
200 g of AgNO₃ will produce = X g of Ag
Solving for X,
X = (200 g × 215.7 g) ÷ 339.74 g
X = 126.97 g Ag
Next calculate for 100 g of Cu,
According to equation,
63.52 g (1 mole) Cu produced = 215.7 g (2 mole) of Ag
So,
100 g of Cu will produce = X g of Ag
Solving for X,
X = (100 g × 215.7 g) ÷ 63.52 g
X = 339.57 g Ag
Result:
As 200 g of AgNO₃ is producing Ag in less amount (126.97 g) as compared to 100 g of Cu, it means that AgNO₃ is in limited amount and will consume first till the production of 126.97 g of Ag. So, the maximum amount of Ag production is 126.97 g.
