Respuesta :
Answer: 0.83 M
Explanation: Molarity is moles of solute per liter of solution.
Mass of solute(acetic acid) is given as 5.0 g and the volume of solution is 100.0 mL.
We need to convert the grams of acetic acid to moles and for this we divide the grams by molar mass.
Formula of acetic acid is [tex]CH_3COOH[/tex] . Molar mass of acetic acid = 2(12.01) + 4(1.01) + 2(16)
= 24.02 + 4.04 + 32
= 60.06 grams per mol
moles of acetic acid = 5.0/60.06 = 0.083 moles
Convert mL to L.
we know that, 1 L = 1000 mL
So, to convert mL to L we divide by 1000.
[tex]\frac{100.0}{1000}[/tex] = 0.1000 L
molarity of the solution = [tex]\frac{0.083moles}{0.1000L}[/tex]
= 0.83M
So, the molarity of acetic acid in vinegar is 0.83 M.
Vinegar contains 5.0g of acetic acid in 100.0 ml of solution, the molarity of acetic acid in vinegar is 0.83 M.
What is molarity?
Molarity of any solution will be define as the number of moles of the solute present in per liter of the solution and it is represented as:
M = n/V
Moles of the acetic acid will be calculated as:
n = W/M , where
W = given mass = 5g
M = molar mass = 60g/mol
n = 5g / 60g/mol = 0.083 moles
Molarity of the acetic acid in 100mL or 0.1 L will be calculated as:
M = 0.083 / 0.1 = 0.83 M
Hence required molarity is 0.83 M.
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