Respuesta :

MarkV
Hi there!

We can use the FOIL technique to find our answer.
[tex](x + 2)(x + 4) ={x}^{2} + 6x + 8\\ \\ first \: = x \times x = {x}^{2} \\ outside \: = x \times 4 = 4x \\ inside \: 2 \times x = 2x \\ last \: = 2 \times 4 = 8 \\ \\ answer \\ (x + 2)(x + 4) = {x}^{2} + 2x + 4x + 8 \\ \\ collect \: terms \: to \: get \: final \: answer \\ {x}^{2} + 2x + 4x + 8 ={x}^{2} + 6x + 8[/tex]

~ Hope this helps you!
The first step for solving this problem is to remember the FOIL method. This means that we need to multiply each term in the first parenthesis by each term in the second parenthesis. This will look like the following:
x × x + 4x + 2x + 2 × 4
Now we need to calculate the product of x × x.
x² + 4x + 2x + 2 × 4
Multiply the numbers 2 and 4 together.
x² + 4x + 2x + 8
Next we need to collect the like terms,, which we can start doing by adding together their coefficients.
(4 + 2)x
Add the numbers in the parenthesis together to find what the collected terms will equal.
6x
Finally,, replace 4x + 2x with 6x and that will be you final answer.
x² + 6x + 8
Since we cannot simplify this expression any further,, your final answer should be x² + 6x + 8.
Let me know if you have any further questions.
:)