A spinner and 4 cards are shown below: A spinner with 5 equal sectors is shown in the figure. The colors Green, Blue, Purple, Yellow, and Red are marked on it. The arrow points at the purple color. Four cards are shown on the right side. The colors Red, Yellow, Blue, and Pink are marked on them. Jane spins the spinner and selects a card without looking. What is the probability that the spinner stops at purple and a pink card is selected? 1 over 20 1 over 5 1 over 4 9 over 20

Respuesta :

[tex] |\Omega|=5\cdot4=20\\
|A|=1\\\\
P(A)=\dfrac{1}{20} [/tex]

The probability that the spinner stops at purple and a pink card is selected is 1/20

How to determine the probability?

The given parameters are:

  • Spinner = {Green, Blue, Purple, Yellow, Red}
  • Cards = {Red, Yellow, Blue, Pink}

There is 1 purple color on the spinner and 1 pink card in the card.

So, the probability that the spinner stops at purple and a pink card is selected is:

P(Purple and Pink) = 1/5 * 1/4

Evaluate the product

P(Purple and Pink) = 1/20

Hence, the probability that the spinner stops at purple and a pink card is selected is 1/20

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