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help asap please!! An aluminum block of mass 12.00 kg is heated from 20 C to 118 C. If the specific heat of aluminum is 913 J-1 kg K-1 then how much energy is required?
A. 10.956 kJ
B. 1073.688 kJ
C. 64.640 kJ
D. 7456.167 kJ

Respuesta :

jushmk
Q = mCΔT, where Q = Amount of energy required, m = mass of the blcok, C = specific heat, ΔT = change in temperature.

Using the given values;

Q = 12*913*(118-20) = 1073688 J = 1073.688 kJ.

The correct answer in B.

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