Given that the geometric series is given by:
f(n)=an=1.2f(n-1) where a1=6, then f(38) will be found as follows:
a2=1.2f(2-1)=1.2f(1)=1.2*6=7.2
a3=1.2f(3-1)=1.2f(2)=8.64
thus the common ratio is r=1.2
but
explicit formula for geometric sequence is:
an=ar^(n-1)
thus plugging our values:
f(38)=6(1.2)^(38-1)
f(38)=5103.3735
Answer: C) 5103.3735
