Respuesta :
The answer is 6.88.
Solution:
We can calculate for the percent composition of CaCl2 by mass by dividing the mass of the CaCl2 solute by the mass of the solution and then multiply by 100. The total mass of the resulting solution is the sum of the mass of CaCl2 solute and the mass of water solvent. Therefore, the percent composition of CaCl2 by mass is
% by mass = (mass of the solute / mass of the solution)*100
= mass of solute / (mass of the solute + mass of the solvent)*100
= (27.7 g CaCl2 / 27.7g + 375g) * 100
= 6.88
Solution:
We can calculate for the percent composition of CaCl2 by mass by dividing the mass of the CaCl2 solute by the mass of the solution and then multiply by 100. The total mass of the resulting solution is the sum of the mass of CaCl2 solute and the mass of water solvent. Therefore, the percent composition of CaCl2 by mass is
% by mass = (mass of the solute / mass of the solution)*100
= mass of solute / (mass of the solute + mass of the solvent)*100
= (27.7 g CaCl2 / 27.7g + 375g) * 100
= 6.88
The concentration of [tex]{\text{CaC}}{{\text{l}}_{\text{2}}}[/tex] is [tex]\boxed{6.88\;\%}[/tex] by mass.
Further Explanation:
The proportion of substance in the mixture is called concentration. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Mass percent:
It is the ratio of the mass of a component divided by the total mass of the solution, multiplied by 100.
The formula to calculate the mass percent of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] is as follows:
[tex]{\text{Mass}}\;{\text{percent of CaC}}{{\text{l}}_2} = \left( {\frac{{{\text{Mass of CaC}}{{\text{l}}_{\text{2}}}}}{{{\text{Mass of CaC}}{{\text{l}}_2}\;{\text{solution}}}}} \right)\left( {100} \right)[/tex] …… (1)
The formula to calculate the mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] solution is as follows:
[tex]{\text{Mass of CaC}}{{\text{l}}_{\text{2}}}{\text{ solution}} = {\text{Mass of CaC}}{{\text{l}}_{\text{2}}} + {\text{Mass of water}}[/tex] …… (2)
The mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] is 27.7 g.
The mass of water is 375 g.
Substitute these values in equation (2).
[tex]\begin{aligned}{\text{Mass of CaC}}{{\text{l}}_{\text{2}}}{\text{ solution}}&=27.7{\text{ g}}+{\text{375 g}}\\&={\text{402}}{\text{.7 g}}\\\end{aligned}[/tex]
The mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] is 27.7 g.
The mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex]solution is 402.7 g.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Mass}}\;{\text{percent of CaC}}{{\text{l}}_2}&=\left( {\frac{{{\text{27}}{\text{.7 g}}}}{{{\text{402}}{\text{.7 g}}}}} \right)\left( {100} \right)\\&=6.8785\;\%\\&\approx 6.8{\text{8 \% }}\\\end{aligend}[/tex]
Therefore the mass percent of [tex]{\mathbf{CaC}}{{\mathbf{l}}_{\mathbf{2}}}[/tex] is 6.88 %.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: mass percent, 6.88 %, mass of CaCl2, mass of water, mass of CaCl2, concentration, CaCl2, 27.7 g, 375 g, 402.7 g.
