Respuesta :

4s²3d¹⁰4p⁵

4 in 4p⁵ shows that an element is in the 4th period,
4s²4p⁵   (2+5=7) shows that element is in 17 group, if we have p-electrons on the last level, we need to count s-electrons and p-electrons, and then we will see number of the group, where an element is. 7 s- and p- electrons on the last level, so element in 17th group.

4th period, 17th group - it is Br.
Histrionicus

The element that has a ground-state electron configuration of [ar]4s23d104p5  - bromine (br)

Electron configurations are the representation of the electrons are around a nucleus.

  • electronic configuration is  [Ar]4s23d104p5  
  • [Ar] or argon has 18 electrons.
  • In 4S orbital, there are 2 electrons, 3d orbital there are 10 electrons, and 4p orbital, there are 5 electrons.
  • Total number of electrons = 18+2+10+5 = 35.
  • Atomic number (Z) is the number of electrons present in an atom.
  • Therefore, the atomic number of a given element is 35.
  • 35 is the atomic number of bromine

Thus, the element that has a ground-state electron configuration of [ar]4s23d104p5  - bromine (br)

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