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What is the wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v? express your answer in terms of λ0, c, and v?

Respuesta :

When an electromagnetic wave moves from a medium to another medium, its frequency remains constant. In this problem, we have light (which is an electromagnetic wave) moving from air to glass (or vice-versa), so we can write
[tex]f_0 = f[/tex] (1)
where [tex]f_0[/tex] is the frequency of the light in air, while f is the frequency in glass.

Using the relationship between frequency, wavelenght and speed of a wave, we have
[tex]f= \frac{v}{\lambda} [/tex]
where v is the speed of light in glass and [tex]\lambda[/tex] the wavelength in glass, and
[tex]f_0 = \frac{c}{\lambda_0} [/tex]
where c is the speed of light in air and [tex]\lambda_0[/tex] the wavelength in air. Using these two relationships, we can rewrite eq.(1) as
[tex] \frac{c}{\lambda_0}= \frac{v}{\lambda} [/tex]
and by re-arranging it, we find
[tex]\lambda= \frac{v}{c} \lambda_0 [/tex]

The wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v will be

[tex]\lambda=\dfrac{v}{c}\lambda_o[/tex]

What is wavelength?

The wavelength of any wave is defined as the distance between two max adjacent amplitudes, or the distance between two successive troughs or crest.

When an electromagnetic wave moves from a medium to another medium, its frequency remains constant. In this problem, we have light (which is an electromagnetic wave) moving from air to glass (or vice-versa), so we can write

[tex]f_o=f(1)[/tex] (1)

where  is the frequency of the light in air, while f is the frequency in glass.

Using the relationship between frequency, wavelenght and speed of a wave, we have

[tex]f=\dfrac{v}{\lambda}[/tex]

where v is the speed of light in glass and  the wavelength in glass, and

[tex]f_o=\dfrac{c}{\lambda_o}[/tex]

where c is the speed of light in air and  the wavelength in air. Using these two relationships, we can rewrite eq.(1) as

[tex]\dfrac{c}{\lambda_o}=\dfrac{v}{\lambda}[/tex]

and by re-arranging it, we find

[tex]\lambda=\dfrac{v}{c} \lambda_o[/tex]

Hence the wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v will be

[tex]\lambda=\dfrac{v}{c}\lambda_o[/tex]

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