Respuesta :

Surface area #1:  4*pi*r^2

Surface area #2:  4*pi*(2r)^2      This is 4 times larger than the previous                                                                  surface area.

Answer:

Option 2 - [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Given : The radius of one sphere is twice as great as the radius of a second sphere.

To find : The ratio of their surface areas?

Solution :

The surface area of the sphere is [tex]A=4\pi r^2[/tex]

Let, the radius of one sphere is r

The surface area of one sphere is [tex]A_1=4\pi r^2[/tex]

Radius of second sphere is R

The surface area of second sphere is [tex]A_2=4\pi R^2[/tex]

According to question,

The radius of one sphere is twice as great as the radius of a second sphere.  

i.e, r=2R

Now, The ratio of their surface areas is

[tex]Ratio=\frac{A_2}{A_1}[/tex]

[tex]Ratio=\frac{4\pi R^2}{4\pi r^2}[/tex]

Substitute r=2R,

[tex]Ratio=\frac{4\pi R^2{4\pi (2R)^2}}[/tex]

[tex]Ratio=\frac{4\pi R^2}{16\pi R^2}[/tex]

[tex]Ratio=\frac{1}{4}[/tex]

Therefore, Option 2 is correct.

The ratio of their surface area is  [tex]\frac{1}{4}[/tex]